When 64.0 g of methanol (CHOH) is burned, 1454 kJ of energy is produced. What is the heat of combustion for methanol?

The heat of combustion for methanol is 727 kj/mol

calculation

calculate the moles of methanol (CH3OH)

moles = mass/molar mass

molar mass of methanol = 12 + (1 x3) + 16 + 1 = 32 g / mol

moles is therefore = 64.0 g / 32 g/mol = 2 moles

Heat of combustion is therefore = 1454 Kj / 2 moles = 727 Kj/mol