31 March, 04:36
Phosphorus-32 has a half-life of 14.3 days. How many milligrams of phosphorus-32 remain after 71.5 days is you start with 4.00 mg of the isotope?
31 March, 05:33
We first calculate the decay constant, λ
λ = ln (2) / half life
λ = ln (2) / 14.3
The decay equation is:
N = N (initial) x exp (-λt)
N = 4 x exp (-ln (2) / 14.3 x 71.5)
N = 0.125 mg will remain
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» Phosphorus-32 has a half-life of 14.3 days. How many milligrams of phosphorus-32 remain after 71.5 days is you start with 4.00 mg of the isotope?