You are producing magnesium oxide by the reaction 2 Mg + O 2 > 2 MgO. If you start out with 6 moles of magnesium, how many moles of oxygen will you need? How many moles of magnesium oxide will you produce?

Question

Maximilian Barton

Chemistry

13 April, 10:43

You are producing magnesium oxide by the reaction 2 Mg + O 2 > 2 MgO. If you start out with 6 moles of magnesium, how many moles of oxygen will you need? How many moles of magnesium oxide will you produce?

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Answers (1)

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Marques Gross · Answer 1

2 Mg + O₂ - -> 2 MgO

If we have 6 moles of magnesium, then we use the ratios from the balanced equation to find the moles of oxygen needed

MOLES O₂ = MOLES MG * (1 O₂ / 2 Mg) <-- - we get this from equation

= 6 mol Mg * (1 O₂ / 2 Mg)

= 3 mol O₂

We need 3 moles of oxygen otherwise we will not have all 6 moles of magnesium react. This will product

MOLES MgO = MOLES MG * (2 MgO / 2 Mg)

= 6 mol Mg * (2 MgO / 2 Mg)

= 6 mol MgO

We will produce 6 moles of magnesium oxide