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20 February, 15:32

When the pressure changes from 1.21 atm to 2.52 atm, the volume changes from 3.75 L to 1.72 L and the temperature changes from 293 K to _ k

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  1. 20 February, 15:45
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    Answer is 280 K

    Explanation:

    Let's assume that the gas is an ideal gas.

    Then we can use combined gas law,

    PV/T = k (constant)

    Where, P is the pressure of the gas, V is volume of the gas and T is the temperature of the gas in Kelvin.

    For two situations, we can use

    P₁V₁/T₁ = P₂V₂/T₂

    P₁ = 1.21 atm

    V₁ = 3.75 L

    T₁ = 293 K

    P₂ = 2.52 atm

    V₂ = 1.72 L

    T₂ = ?

    From substitution,

    1.21 atm x 3.75 L / 293 K = 2.52 atm x 1.72 L / T₂

    T₂ = (2.52 atm x 1.72 L x 293 K) / (1.21 atm x 3.75 L)

    T₂ = 279.9 K

    T₂ = 280 K
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