If 0.3041 g of a diprotic solid acid is neutralized by 35.45 ml of 0.0997 m naoh, calculate the malar mass of solid acid

Number of moles required to neutralize the solution=0.0354*0.0997

=0.0035mol

2 mol of NaOH required to neutralize 1 mol of diprotic acid.

So moles of acid 0.0035/2=0.0017

Number of moles of acid=Mass of diprotic acid/Molar mass of diprotic acid

0.0017 = 0.3041/Molar mass of diprotic acid

Molar mass of diprotic acid=0.3041/0.0017

=178.8 g/mol