When Sodium Hydroxide and Sulfuric Acid are mixed together, a neutralization reaction occurs. If 2.26 grams of sodium hydroxide are mixed with 4.19 grams of sulfric acid, what will the amounts be of water and sodium sulfate when the reaction is complete? How would start and solve the problem?

Amount of sodium sulphate is 5.64g

Amount of water is 1.017g

Explanation:

First give a balanced equation for the reaction

2NaOH + H2SO4 > Na2SO4 + 2H2O

Find the number of moles of each reacting specie by dividing the mass by their molar mass

Use the number of moles to find the amount in the product

For 2NaOH

2.26/80=0.02825moles

0.02825 x molar mass of 2H2O = 1.017g

For H2SO4

4.19/98=0.0428moles

0.0428 x 132 = 5.64g