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17 June, 00:34

The average propane cylinder for a residential grill holds approximately 18 kg of propane. how much energy (in kj) is released by the combustion of 20.00 kilograms of propane in sufficient oxygen?

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  1. 17 June, 00:44
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    Let's begin with the basic values that will be used in the solution.

    The formula of propane is C3H8. It is an alkane, a hydrocarbon with the general formula of CnH2n+2. Notice that hydrocarbons have only Carbon and Hydrogen atoms. Its molar mass (M) is 44 g.

    Molar Mass Calculation is done as like that

    C=12 g/mol, H=1 g/mol. 1 mole propane has 3 moles Carbon atoms and 8 mole Hydrogen atoms. M (C3H8) = 3*12 + 8*1 = 44 g

    Combustion reaction of hydrocarbons gives carbon dioxide and water by releasing energy. That energy is called as enthalpy of combustion (ΔHc°).

    ΔHc° of propane equals - 2202.0 kj/mol. Burning of 1 mole C3H8 releases 2202 kj energy. Minus sign only indicates that the energy is given out (an exothermic reaction).

    Let's write the combustion reaction.

    C3H8 + O2 - - - > CO2 + H20 (unbalanced) ΔHc° = - 2202 kj/mol

    Now, we calculate mole of 20 kg propane. Convert kilogram into gram since we use molar mass is defined in grams.

    mole=mass/molar mass; n=m/M; n = 20000 g / 44 (g/mol) = 454 mole

    1 mole propane releases 2202 kj energy.

    454 mole propane release 2202 kj * 454 = 1000909 kj

    The answer is 1000909 kj.
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