assume that you used a 0.660 g piece of pure aluminum in the synthesis of alum and obtained a 63.5% yield of alum. How many grams of alum did you obtain?

1.015g

Explanation:

From the question,

Mass of Al used = 0.660g

The percentage yield = 63.5%

Mass of Alum used = y

To find the mass of Alum used, do the following:

%yield = Mass of Al / Mass and Alum

65% = 0.660/y

65/100 = 0.660/y

Cross multiply

65 x y = 0.660x100

Divide both side by 65

y = (0.660x100) / 65

y = 1.015g

The mass of alum obtained is 1.015g