A major component of gasoline is octane (C8H18). When liquid octane is burned in air it reacts with oxygen gas to produce carbon dioxide gas and water vapor.

Calculate the moles of water produced by the reaction of 1.00 mol of oxygen. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant figures

Question

Nayeli Bonilla

Chemistry

23 March, 18:23

A major component of gasoline is octane (C8H18). When liquid octane is burned in air it reacts with oxygen gas to produce carbon dioxide gas and water vapor.

Calculate the moles of water produced by the reaction of 1.00 mol of oxygen. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant figures

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Answers (1)

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Elaine Serrano · Answer 1

We'll have 0.72 moles of H2O produced

Explanation:

Step 1: Data given

Number of moles oxygen = 1.00 moles

Step 2: The balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Step 3: Calculate the number of moles of H2O

For 2 moles octane we need 25 moles O2 to produce 16 moles CO2 and 18 moles H2O

For 1.00 mol of oxygen we'll have 18/25 * 1.00 moles = 0.72 moles of H20

We'll have 0.72 moles of H2O produced