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23 July, 19:39

How many grams of kcl are present in 85.0 ml of 2.10 m kcl? how many grams of kcl are present in 85.0 ml of 2.10 m kcl? 3.02 133 13.3 6.34 none of the above?

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  1. 23 July, 19:47
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    Molarity (M) = moles of the solute (mol) / Volume of the solution (L)

    The molarity of the given KCl solution = 2.10 M

    Volume of the given KCl solution = 85.0 mL

    Hence,

    2.10 M = Moles of KCl / 85.0 x 10⁻³ L

    Moles of KCl = 2.10 M x 85.0 x 10⁻³ L

    = 0.1785 mol

    Moles (mol) = Mass (g) / Molar mass (g mol⁻¹)

    Molar mass of KCl = 74.56 g mol⁻¹

    Hence,

    0.1785 mol = Mass of KCl / 74.56 g mol⁻¹

    Mass of KCl = 0.1785 mol x 74.56 g mol⁻¹

    = 13.30 g

    Hence, mass of given KCl in 85.0 mL is 13.30 g.
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