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25 November, 17:52

A race car driver starts a race with his tires at 13.2 psi at a temperature of 25 C. What will the pressure in the tires be (in psi) when they heat up to 63 C?

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  1. 25 November, 18:04
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    P₂ = 14.88 psi

    Explanation:

    Given dа ta:

    Initial pressure of tires = 13.2 psi

    Initial temperature = 25°C (25+273 = 298 K)

    Final pressure in tires = ?

    Final temperature = 63°C (63+273 = 336 K)

    Solution:

    According to Gay-Lussac Law,

    The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

    Mathematical relationship:

    P₁/T₁ = P₂/T₂

    Now we will put the values in formula:

    13.2 / 298 K = P₂/336 K

    P₂ = 13.2 psi * 336 K / 298 K

    P₂ = 4435.2 psi. K / 298 K

    P₂ = 14.88 psi
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