For the reaction Ag 2S (s) ⇌ 2Ag + (aq) + S 2 - (aq), what happens to the equilibrium position if the amount of silver ion is halved?

Question

Kenyon

Chemistry

18 June, 20:00

For the reaction Ag 2S (s) ⇌ 2Ag + (aq) + S 2 - (aq), what happens to the equilibrium position if the amount of silver ion is halved?

+3

Answers (1)

Know the Answer?

Giuliana Harding · Answer 1

the equilibrium shifts from left to right

Explanation:

The rule, known as Le Châtelier principle, states that if an external stress is applied to a system al equilibrium, the system adjusts in such a way that the stress is partially offset as the system reaches a new equilibrium position. In this case "stress" is a change in concentration.

When the concentration of silver ion is halved, more Ag2S units dissociate in order to reach a new equilibrium position, thus the equilibrium shifts from left to right

Remember. chemical equilibrium is achieved when the rates of the forward and reverse reactions are equal and the concentrations of the reactants (Ag2S) and products (Ag and S) remain constant.