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23 August, 03:20

How many grams of water must be added to 455 grams of potassium sulfate in order to make a 1.50 m solution?

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  1. 23 August, 04:39
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    Molar mass of K₂SO₄ = 174.3 g/mol

    Mass of K₂SO₄ = 455 g

    Moles = mass / molar mass

    Hence, moles of K₂SO₄ = 455 g / 174.3 g/mol

    = 2.61 mol

    Molarity = moles of solute (mol) / Volume of the solution (L)

    Hence, volume = moles of solute / molarity

    = 2.61 mol / 1.50 M

    = 1.742 L = 1742 mL

    Hence, needed volume of water = 1742 mL

    Density = mass / volume

    Density of water = 0.9972 g/mL

    Hence mass of water = 0.9972 g/mL x 1742 mL

    = 1737.12 g

    Hence, needed mass of water = 1737.12 g.
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