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2 September, 04:06

Consider the balanced equation of aluminum reacting with sulfuric acid. 2 A l + 3 H 2 S O 4 ⟶ A l 2 (S O 4) 3 + 3 H 2 Determine how many atoms of each element are present on each side of the arrow.

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  1. 2 September, 04:21
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    Al = 2 atoms.

    H = 6atoms.

    S = 3 atom.

    O = 12 atoms

    Explanation:

    2Al + 3H2SO4 - > Al2 (SO4) 3 + 3H2

    From the balanced equation, the number of atoms of the different elements present on both sides as

    Al = 2 atoms.

    H = 6 atoms.

    S = 3 atoms.

    O = 12 atoms
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