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30 May, 04:16

In the Haber process, 30.00 g of nitrogen gas is combined with 30.00 g of hydrogen gas to form ammonia gas, NH3. What mass, in grams, of ammonia will form?

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  1. 30 May, 04:26
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    Mass = 36.38 g

    Explanation:

    Given dа ta:

    Mass of hydrogen = 30.0 g

    Mass of nitrogen = 30.0 g

    Theoretical yield of reaction = ?

    Mass of ammonia = ?

    Chemical equation:

    N₂ + 3H₂ → 2NH₃

    Number of moles of N₂:

    Number of moles = Mass / molar mass

    Number of moles = 30 g / 28 g/mol

    Number of moles = 1.07 mol

    Number of moles of H₂:

    Number of moles = Mass / molar mass

    Number of moles = 30 g / 2g/mol

    Number of moles = 15 mol

    Now we will compare the moles of NH₃ with hydrogen and nitrogen.

    H₂ : NH₃

    3 : 2

    15 : 2/3*15 = 10 mol

    N₂ : NH₃

    1 : 2

    1.07 : 2 * 1.07 = 2.14 mol

    The number of moles of NH₃ produced by nitrogen are less it will be limiting reactant.

    Mass of ammonia:

    Mass of NH₃ = moles * molar mass

    Mass = 2.14 mol * 17 g/mol

    Mass = 36.38 g
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