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17 November, 07:40

The ksp of yttrium fluoride, yf3, is 8.62 * 10-21. calculate the molar solubility of this compound.

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  1. 17 November, 07:57
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    Answer is: molar solubility of yttrium fluorid is 4.23·10⁻⁶ M.

    Balanced chemical reaction: YF ₃ (s) → Y³⁺ (aq) + 3F⁻ (aq).

    Ksp = 8.62·10 ⁻²¹.

    Ksp = [ Y³⁺] · [F⁻]³.

    [Y³⁺] = [YF₃] = s.

    [F⁻] = 3[YF₃] = 3s.

    Ksp (YF₃) = s · (3s) ³.

    8.62·10⁻²¹ = 27s⁴.

    s (YF₃) = ⁴√ (8.62·10⁻²¹ : 27).

    s (YF₃) = 0.00000423 M.

    s (YF₃) = 4.23·10⁻⁶ M.
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