6 C (s) + 3 H2 (g) → 2 C6H6 (l) Δ H = 49 kJ

TRUE or FALSE

Question

Kamari Miller

Chemistry

3 June, 04:41

6 C (s) + 3 H2 (g) → 2 C6H6 (l) Δ H = 49 kJ

TRUE or FALSE

+5

Answers (1)

Know the Answer?

Mila Nash · Answer 1

True = > ΔH°f for C₆H₆ = 49 Kj/mole

Explanation:

See Thermodynamic Properties Table in appendix of most college level general chemistry texts. The values shown are for the standard heat of formation of substances at 25°C. The Standard Heat of Formation of a substance - by definition - is the amount of heat energy gained or lost on formation of the substance from its basic elements in their standard state. C₆H₆ (l) is formed from Carbon and Hydrogen in their basic standard states. All elements in their basic standard states have ΔH°f values equal to zero Kj/mole.

6 C (s) + 3 H2 (g) → 2 C6H6 (l) Δ H = 49 kJTRUE or FALSE

6 C (s) + 3 H2 (g) → 2 C6H6 (l) Δ H = 49 kJ

TRUE or FALSE