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31 May, 11:16

If an aqueous solution contains 70% of Isopropyl Alcohol (d = 0.786 g/ml):

a: how many ml are alcohol?

b: how many ml are water?

c: how many grams of alcohol were used to prepare this solution?

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Answers (1)
  1. 31 May, 11:19
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    A. 70mL.

    B. 30mL.

    C. 55.02g.

    Explanation:

    Data obtained from the question include:

    Percentage of Isopropyl Alcohol = 70%

    Density of Isopropyl Alcohol = 0.786g/mL

    Percentage of the solution = 100%

    A. Determination of the volume of the alcohol.

    Percentage volume of solute =

    volume of solute / Volume of solution x

    100

    70% = volume of solute/100

    70/100 = volume of solute / 100

    Cross multiply

    Volume of solute = 70/100 x 100

    Volume of solute = 70mL.

    Therefore, the volume of the alcohol is 70mL.

    B. Determination of the volume of water.

    Volume of solute (alcohol) = 70mL

    Volume of solution = 100mL

    Volume of water = ... ?

    Volume of solution = volume solute + volume of water

    100 = 70 + volume of water

    Collect like terms

    Volume of water = 100 - 70 = 30mL

    Therefore, the volume of water is 30mL

    C. Determination of the mass of alcohol in the solution

    Density of Isopropyl Alcohol = 0.786g/mL

    Volume of Isopropyl Alcohol = 70mL

    Mass of Isopropyl Alcohol =.?

    Density = Mass / volume

    0.786 = Mass / 70

    Cross multiply

    Mass = 0.786 x 70

    Mass = 55.02g

    Therefore, the mass of the alcohol used in preparing the solution is 55.02g.
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