A 0.43g sample of potassium hydrogen phthalate required 24.11cm³ NaOH for neutralization. Calculate the molarity of the NaOH

Answer

The mole ratio is 1:1

The molar mass of potassium hydrogen phthalate (C8H5KO4) is 204.22g/mol

The mass of C8H5KO4 is 0.43g

The no of moles of C8H5KO4 = mass/molar mass

No of Moles of C8H5KO4 = 0.000210557242mol

From Mole ratio the no of mole of NaOH that reacted with C8H5KO4 0.000210557242

Therefore, molaroty of NaOH is mole of NaOH/the Volume in L

Molaroty if NaOH = 0.000210557242/0.02411 = 0.08733M