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22 November, 23:46

A 0.43g sample of potassium hydrogen phthalate required 24.11cm³ NaOH for neutralization. Calculate the molarity of the NaOH

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  1. 23 November, 00:14
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    The mole ratio is 1:1

    The molar mass of potassium hydrogen phthalate (C8H5KO4) is 204.22g/mol

    The mass of C8H5KO4 is 0.43g

    The no of moles of C8H5KO4 = mass/molar mass

    No of Moles of C8H5KO4 = 0.000210557242mol

    From Mole ratio the no of mole of NaOH that reacted with C8H5KO4 0.000210557242

    Therefore, molaroty of NaOH is mole of NaOH/the Volume in L

    Molaroty if NaOH = 0.000210557242/0.02411 = 0.08733M
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