In the following reaction 6.13g of water (H2O) is produced the theoretical

yield of water (H2O) is 8.17g, what is the percent yield of water? *

C3H8+5 02 3 CO2 + 4 H2O

A) 85.0%

B) 72.0%

C) 75.0%

D) 67.0%

Question

Sanaa Wagner

Chemistry

16 July, 00:33

In the following reaction 6.13g of water (H2O) is produced the theoretical

yield of water (H2O) is 8.17g, what is the percent yield of water? *

C3H8+5 02 3 CO2 + 4 H2O

A) 85.0%

B) 72.0%

C) 75.0%

D) 67.0%

+2

Answers (1)

Know the Answer?

Acevedo · Answer 1

C = 75%

Explanation:

Theoretical yield = 8.17g

Actual yield = 6.13g

To calculate the percentage yield of a compound in a reaction, we'll use the formula to calculate it

Percentage yield = (actual yield / theoretical yield) * 100

% yield = (6.13/8.17) * 100

Percentage yield = 0.7503 * 100

Percentage yield = 75.03%

In the following reaction 6.13g of water (H2O) is produced the theoreticalyield of water (H2O) is 8.17g, what is the percent yield of water? *C3H8+5 02 3 CO2 + 4 H2OA) 85.0%B) 72.0%C) 75.0%D) 67.0%

In the following reaction 6.13g of water (H2O) is produced the theoretical

yield of water (H2O) is 8.17g, what is the percent yield of water? *

C3H8+5 02 3 CO2 + 4 H2O

A) 85.0%

B) 72.0%

C) 75.0%

D) 67.0%