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16 July, 00:33

In the following reaction 6.13g of water (H2O) is produced the theoretical

yield of water (H2O) is 8.17g, what is the percent yield of water? *

C3H8+5 02 3 CO2 + 4 H2O

A) 85.0%

B) 72.0%

C) 75.0%

D) 67.0%

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Answers (1)
  1. 16 July, 01:00
    0
    C = 75%

    Explanation:

    Theoretical yield = 8.17g

    Actual yield = 6.13g

    To calculate the percentage yield of a compound in a reaction, we'll use the formula to calculate it

    Percentage yield = (actual yield / theoretical yield) * 100

    % yield = (6.13/8.17) * 100

    Percentage yield = 0.7503 * 100

    Percentage yield = 75.03%
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