How many moles of oxygen are present in 33.6l of the gas at 1atm and 0c

Question

Junior Kemp

Chemistry

7 June, 21:49

How many moles of oxygen are present in 33.6l of the gas at 1atm and 0c

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Steven · Answer 1

The answer is: 1.5 moles of oxygen are present.

V (O₂) = 33.6 L; volume of oxygen.

p (O₂) = 1.0 atm; pressure of oxygen.

T = 0°C; temperature.

Vm = 22.4 L/mol; molar volume at STP (Standard Temperature and Pressure).

At STP one mole of gas occupies 22.4 liters of volume.

n (O₂) = V (O₂) : Vm.

n (O₂) = 33.6 L : 22.4 L/mol.

n (O₂) = 1.50 mol; amount of oxygen.