How many grams of ethanol c2h5oh can be made by the fermentation of 1150 g of glucose?

Question

Iyana Quinn

Chemistry

12 November, 17:01

How many grams of ethanol c2h5oh can be made by the fermentation of 1150 g of glucose?

+5

Answers (1)

Know the Answer?

Kenley Fuentes · Answer 1

Answer is: 588.15 grams of ethanol.

Chemical reaction: C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂.

m (C₆H₁₂O₆) = 1150 g.

n (C₆H₁₂O₆) = m (C₆H₁₂O₆) : M (C₆H₁₂O₆).

n (C₆H₁₂O₆) = 1150 g : 180.16 g/mol.

n (C₆H₁₂O₆) = 6.38 mol.

From chemical reaction: n (C₆H₁₂O₆) : n (C₂H₅OH) = 1 : 2.

n (C₂H₅OH) = 12.76 mol.

m (C₂H₅OH) = 12.76 mol · 46.07 g/mol.

m (C₂H₅OH) = 588.15 g.