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30 September, 07:22

Use valence bond theory to describe the number and types of hybrid bonding orbitals on the central atom of each of the following. (a) BCl4 - type of hybridization: sp-hybridization sp2-hybridization sp3-hybridization sp3d-hybridization sp3d2-hybridization In BCl4-, boron has hybrid orbital (s).

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  1. 30 September, 07:31
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    The central atom boron in BCl₄⁻ ion is sp³ hybridized and has 4 sp³ hybrid orbitals.

    Explanation:

    Boron is an element which belongs to group 13 of periodic table.

    According to the Valence Bond Theory, in BCl₄⁻ ion, one 2s and three 2p orbitals of boron hybridize to form four sp³ hybrid orbitals, which overlap with four 2p orbitals of chlorine to form BCl₄⁻ anion.

    Therefore, the central atom boron in BCl₄⁻ ion is sp³ hybridized and has 4 sp³ hybrid orbitals.
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