What mass of bromine reacts with 16.2 g of aluminium?

For every, 3 Br - ions, 1 Al3 + ion reacts to form AlBr3.

Convert 16.2g of aluminum to moles:

16.2g Al / 27.0g per mol = 0.60 mols.

Based on the above ratio, 0.60 mols of Al will react with 1.8 mols of Br.

Convert 1.8 mols of Br to its mass:

1.8 mols Br * 79.9g per mol = 143.82g of Br.