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28 September, 18:36

Determine the direction of electron flow and label the anode and the cathode. label each electrode as negative or positive. write a balanced equation for the overall reaction

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  1. 28 September, 18:44
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    At anode is where oxidation takes place, that is

    Cr (s) →Cr3 + (aq) + 3e - this is the oxidation

    At cathode is where reduction takes place,

    Fe3 + (aq) + 3e-→Fe (s). This is the reduction

    Cell reaction is

    Cr (s) →Cr3 + (aq) + 3e - where E°=0.73V

    Fe3 + (aq) + 3e-→Fe (s) where E° = - 0.036V

    Cr (s) + Fe3 + (aq) →Cr3 (aq) + Fe (s) E°cell=0.69V

    Cell reaction for Cr (s) + Fe3 + (aq) → Cr3 + (aq) + Fe (s) is

    E°cell is 0.69V
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