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26 November, 08:59

A solution has a [oh-] of 1 x 10-12. what is the poh of this solution? 2 7 10 12

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  1. 26 November, 09:13
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    POH = - log [ OH-]

    pOH = - log [ 1 x 10⁻¹²]

    pOH = 12
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