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19 November, 06:20

How many grams of methane gas (CH4) are in a 15.8-liter sample at 1.2 atmospheres and 27°C? Show all work used to solve this problem

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  1. 19 November, 06:41
    0
    12.31 g

    Solution:

    Let us suppose that the gas is acting ideally, then according to Ideal Gas Equation,

    P V = n R T

    Also,

    n = Mass / M. mass = m / M

    So,

    P V = m/M R T

    Solving for m,

    m = P V M / R T

    Data Given:

    P = 1.2 atm

    V = 15.8 L

    M = 16 g/mol

    T = 27 C + 273 = 300 K

    R = 0.0821 atm. L/mol. K

    Putting Values,

    m = (1.2 atm * 15.8 L * 16 g/mol) / (0.0821 atm. L/mol. K * 300 K)

    m = 12.31 g
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