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4 August, 14:39

How many grams of NaHCO3 are needed to prepare 250 mL of 0.50 M

NaHCO3?

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  1. 4 August, 14:48
    0
    10.5g

    Explanation:

    First, let us calculate the number of mole of NaHCO3 present in the solution. This is illustrated below:

    Volume = 250mL = 250/1000 = 0.25L

    Molarity = 0.5M

    Mole = ?

    Molarity = mole / Volume

    Mole = Molarity x Volume

    Mole = 0.5 x 0.25

    Mole = 0.125 mole

    Now, we shall be converting 0.125 mole of NaHCO3 to grams to obtain the desired result. This can be achieved by doing the following:

    Molar Mass of NaHCO3 = 23 + 1 + 12 + (16x3) = 23 + 1 + 12 + 48 = 84g/mol

    Number of mole of NaHCO3 = 0.125 mole

    Mass of NaHCO3 = ?

    Mass = number of mole x molar Mass

    Mass of NaHCO3 = 0.125 x 84

    Mass of NaHCO3 = 10.5g

    Therefore, 10.5g of NaHCO3 is needed.
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