A chemist adds 345.0 mL of a 0.520 mol/L of a barium chlorate solution to a reaction flask. Calculate the mass in grams of barium chlorate the chemist has added to the flask. Round your answer to significant digits.

The mass of barium chlorate is 54.6 grams

Explanation:

Step 1: Data given

Barium chlorate = Ba (ClO3) 2

Volume of the barium chlorate solution = 345.0 mL = 0.345 L

Concentration of the barium chlorate solution = 0.520 M

Molar mass of barium chlorate = 304.23 g/mol

Step 2: Calculate moles Ba (ClO3) 2

Moles Ba (ClO3) 2 = volume of Ba (ClO3) 2 solution * concentration of Ba (ClO3) 2

Moles Ba (ClO3) 2 = 0.345 L * 0.520 M

Moles Ba (ClO3) 2 = 0.1794 moles

Step 3: calculate mass of Ba (ClO3) 2

Mass Ba (ClO3) 2 = moles Ba (ClO3) 2 * molar mass Ba (ClO3) 2

Mass Ba (ClO3) 2 = 0.1794 moles * 304.23 g/mol

Mass Ba (ClO3) 2 = 54.6 grams

The mass of barium chlorate is 54.6 grams

54.54g

Explanation:

First, let us obtain the number of mole of Barium chlorate, Ba (ClO3) 2 in the solution. This is illustrated below:

Volume = 345mL = 345/1000 = 0.345L

Molarity = 0.520mol/L

Mole = ?

Molarity = mole / Volume

Mole = Molarity x Volume

Mole = 0.520 x 0.345

Mole = 0.1794mole

Now, we can easily find the mass of the Barium chlorate. This is illustrated below:

Molar Mass of Ba (ClO3) 2 = 137 + 2[35.5 + (16x3) ] = 137 + 2[35.5 + 48] = 137 + 2[83.5] = 137 + 167 = 304g/mol

Number of mole of Ba (ClO3) 2 = 0.1794mole

Mass = ?

Mass = number of mole x Molar Mass

Mass of Ba (ClO3) 2 = 0.1794 x 304

Mass of Ba (ClO3) 2 = 54.54g