Ask Question
4 March, 03:33

The student is now told that the four solids, in no particular order, are barium chloride (BaCl2BaCl2), sugar (C6H12O6C6H12O6), benzoic acid (C6H5COOHC6H5COOH), and potassium bromide (KBrKBr). Assuming that conductivity is correlated to the number of ions in solution, rank the four substances based on how well a 0.20 MM solution in water will conduct electricity. Rank from most conductive to least conductive. To rank items as equivalent, overlap them.

+4
Answers (1)
  1. 4 March, 03:58
    0
    The concept applied is the conductivity as it relates to the dissociation and the number of ions in solution. BaCl2 and KBr are ionic solids that will dissociate completely in water to give trivalent and divalent ions respectively.

    Benzoic acid on the other hand is a weak acid as such it will not dissociate in water. sugar is a covalent compound.

    Hence BaCl2 will have the highest conductivity based on the aforementioned reasons, then followed by KBr; BaCl2 > KBr > C6H5COOH > C6H12O6
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The student is now told that the four solids, in no particular order, are barium chloride (BaCl2BaCl2), sugar (C6H12O6C6H12O6), benzoic ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers