PV=mRT

Where R=0.287 KJ/Kg K

Mass=2 kg, T=35 degrees C, in cubic container with inside demensions of 0.750 meters each side, find pressure in Pa

Question

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Chemistry

11 December, 04:08

PV=mRT

Where R=0.287 KJ/Kg K

Mass=2 kg, T=35 degrees C, in cubic container with inside demensions of 0.750 meters each side, find pressure in Pa

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Answers (1)

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Ireland Schaefer · Answer 1

The answer to your question is: P = 419933.5 Pa

Explanation:

Data

R = 0.287 KJ/Kg°K = 287 J/Kg°K

mass = 2 kg

T = 35 °C = 308°K

Container = 0.750 meters each side

Volume = l x l x l

= 0.750 x 0.750 x 0.750

= 0.421 m³

P = mRT / V

P = (2) (287) (308) / 0.421

P = 176792 / 0.421

P = 419933.5 Pa

PV=mRTWhere R=0.287 KJ/Kg KMass=2 kg, T=35 degrees C, in cubic container with inside demensions of 0.750 meters each side, find pressure in Pa

PV=mRT

Where R=0.287 KJ/Kg K

Mass=2 kg, T=35 degrees C, in cubic container with inside demensions of 0.750 meters each side, find pressure in Pa