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1 February, 09:08

What is the new volume of a gas at standard pressure (760 mm Hg) if originally 2.30 L of the gas had a pressure of 725.0 mmHg?

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  1. 1 February, 09:28
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    2.19L

    Explanation:

    Information from the question include:

    V1 (initial volume) = 2.3L

    P1 (initial pressure) = 725mmHg

    P2 (final pressure) = 760mmHg

    V2 (final volume) = ?

    With the Boyle's law equation P1V1 = P2V2, the final volume can easily be obtain as follow:

    P1V1 = P2V2

    725 x 2.3 = 760 x V2

    Divide both side by 760

    V2 = (725 x 2.3) / 760

    V2 = 2.19L

    Therefore, the new volume of the gas at standard pressure is 2.19L
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