What is the pressure in a 5.00 L tank with 4.75 moles of oxygen at 39.3 degrees Celsius

P = 24.34 atm

Explanation:

V = 5.0L

P = ?

n = 4.75 moles

T = 39.3°C = (39.3 + 273.15) K = 312.45K

From ideal gas equation,

PV = nRT

P = pressure of the gas

V = volume of the gas

n = no. Of moles present

R = ideal gas constant = 0.082atm. L / mol. K

PV = nRT

P = nRT / V

P = (4.75 * 0.082 * 312.45) / 5

P = 121.699 / 5

P = 24.339 atm

P = 24.34 atm

The pressure of the gas is 24.34 atm