2. Matt went to his friend's party. He ate a big meal and drank a keg of beer. He felt heartburn after the meal and took Tums to relieve his heartburn. Unfortunately, he felt reaction happened in his stomach and the product which is CO2 gas was produced. Assume the pressure in Matt's stomach was 780 torr and the amount of the gas was 400mL. What was the volume of the gas after it was released outside of Matt's body? Assume human body temperature is 40°C and room temperature is 25°C. The pressure of the room is 1 atm. 760 torr = 1atm

390.85mL

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 780 torr

Initial volume (V1) = 400mL

Initial temperature (T1) = 40°C = 40°C + 273 = 313K

Final temperature (T2) = 25°C = 25°C + 273 = 298K

Final pressure (P2) = 1 atm = 760torr

Final volume (V2) = ?

Step 2:

Determination of the final volume i. e the volume of the gas outside Matt's body.

The volume of the gas outside Matt's body can be obtained by using the general gas equation as shown below:

P1V1/T1 = P2V2/T2

780 x 400/313 = 760 x V2 / 298

Cross multiply to express in linear form

313 x 760 x V2 = 780 x 400 x 298

Divide both side by 313 x 760

V2 = (780 x 400 x 298) / (313 x 760)

V2 = 390.85mL

Therefore, the volume of the gas outside Matt's body is 390.85mL