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29 November, 22:35

Calculate the new molarity that results when 250. mL of water is added to each of the following solutions.

a) 125 mL of 0.251 M HCI

B) 445 mL of 0.499 M H2SO4

C) 5.25L of 0.101 M HCO3

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  1. 29 November, 22:54
    0
    The answer to your question is 1) 0.037 M 2) 0.32 M 3) 0.096 M

    Explanation:

    a) 125 ml of 0.251 M HCl

    -Calculate the moles of HCl

    Molarity = moles/volume

    -Solve for moles

    moles = Molarity x volume

    -Substitution

    moles = 0.251 x 0.125

    = 0.0314

    -Calculate the new molarity

    Molarity = 0.0314 / (0.125 + 0.250)

    -Simplification

    Molarity = 0.014/0.375

    -Result

    Molarity = 0.037 M

    2.-

    445 ml of 0.499 M of H₂SO₄

    -Calculate the number of moles

    moles = 0.499 x 0.445

    moles = 0.222

    -Calculate the new molarity

    Molarity = 0.222 / (0.445 + 0.25)

    Molarity = 0.222/0.695

    Molarity = 0.32

    3)

    5.25 l of HCO₃ 0.101 M

    Calculate the number of moles

    moles = 0.101 x 5.25

    moles = 0.53

    -Calculate the Molarity

    Molarity = 0.53 / (0.25 + 5.25)

    Molarity = 0.53 / 5.5

    Molarity = 0.096
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