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24 February, 13:52

Calculate the molarity and the molality of an NH3 solution made up of 30.0 g of NH3 in 70.0 g of water. The density of the solution is 0.982 g/mL.

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  1. 24 February, 14:14
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    The formula for molality---> m = moles solute / Kg of solvent

    the solute here is NH₃ because it's the one with less amount. which makes water the solvent.

    1) let's convert the grams of NH₃ to moles using the molar mass

    molar mass of NH₃ = 14.0 + (3 x 1.01) = 17.03 g / mol

    30.0 g (1 mol / 17.03 g) = 1.76 mol NH₃

    2) let's convert the grams of water into kilograms (just divide by 1000)

    70.0g = 0.0700 kg

    3) let's plug in the values into the molality formula

    molality = mol / Kg---> 1.76 mol / 0.070 kg = 25.1 m
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