The volume of a gas collected when the temperature is 11.0 degC and the pressure is 0.934 atm measures 0.0148 L. What is the calculated volume of the gas at 20.0 degC and 0.974 atm?

0.0146cm^3

Explanation:

Using the combined Gas Law P1V1/t1 = P2V2 / t2

P1 ... 0.934

V1 ... 0.0148

T1 ... 11° (284K)

P2 = 0.974

V2 = V2 (unknown)

T2 = 20° (293K)

Hence 0.934x 0.0148 / 284 = 0.974x V2 / 293

0.000048 = 0.974V2 / 293

0.000048 x 293 = 0.974V2

0.01426=0.974V2

V2 = 0.01426 / 0.974

V2 = 0.0146 cm^3