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12 November, 19:14

The concentration of an unknown acid solution with general formula H3A is to be determined by titration with a 0.850 M KOH solution. Determine the concentration of the acid solution given that 38.34 mL of KOH solution were needed to fully neutralize 15.00 mL of the acid solution.

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  1. 12 November, 19:39
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    0.7242 M

    Explanation:

    Step 1:

    Data obtained from the question. This include the following:

    Molarity of base, KOH (Mb) = 0.850 M

    Volume of base, KOH (Vb) = 38.34 mL

    Volume of acid, H3A (Va) = 15.00 mL

    Molarity of acid, H3A (Ma) = ... ?

    Step 2:

    The balanced equation for the reaction. This is given below:

    H3A + 3KOH - > K3A + 3H2O

    From the balanced equation above,

    The mole ratio of the acid, H3A (nA) = 1

    The mole ratio of the base, KOH (nB) = 3

    Step 3:

    Determination of the concentration of the acid, H3A.

    The concentration of the acid, H3A can be obtained as follow:

    MaVa / MbVb = nA/nB

    Ma x 15 / 0.850 x 38.34 = 1/3

    Cross multiply

    Ma x 15 x 3 = 0.850 x 38.34

    Divide both side by 15 x 3

    Ma = (0.850 x 38.34) / (15 x 3)

    Ma = 0.7242 M

    Therefore, the concentration of acid, H3A is 0.7242 M
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