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23 January, 19:22

At 450 mm Hg a gas has a volume of 760 L, what is its volume at standard pressure

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  1. 23 January, 19:35
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    450.0 L.

    Explanation:

    We can use the general law of ideal gas: PV = nRT.

    where, P is the pressure of the gas in atm.

    V is the volume of the gas in L.

    n is the no. of moles of the gas in mol.

    R is the general gas constant,

    T is the temperature of the gas in K.

    If n and T are constant, and have different values of P and V:

    (P₁V₁) = (P₂V₂).

    V₁ = 760.0 L, P₁ = 450.0 mm Hg,

    V₂ = ? L, P₂ = 760.0 mm Hg (standard pressure = 1.0 atm = 760 mm Hg).

    ∴ V₂ = (P₁V₁) / (P₂) = (760.0 L) (450.0 mm Hg) / (760.0 mm Hg) = 450.0 L.
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