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14 July, 16:35

After 56.0 min, 40.0% of a compound has decomposed. What is the half‑life of this reaction assuming first‑order kinetics?

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  1. 14 July, 16:37
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    Go ahead and plug in the percentages and time to find the answer.

    Explanation:

    The amount of a substance with half-life h, that remains after time t is 0.5t/h

    Since 26% has decomposed, 74% remains.

    So. 74 = 0.580/h

    ln. 74 = (80/h) ln 0.5

    h/80 = ln 0.5 / ln. 74

    h = 80 ln 0.5 / ln. 74

    h = 184.16 minutes
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