What are the missing coefficients for the skeleton equation below? Al2 (SO4) 3 (aq) + KOH (aq) ® Al (OH) 3 (aq) + K2SO4 (aq)

You have to balance the chemical equation:

Al2 (SO4) 3 (aq) + KOH (aq) - - - > Al (OH) 3 (aq) + K2SO4 (aq)

To balance that equation you can start by balancing the SO4 radicals. That requires that you place a 3 coefficient before K2SO4 (in the right side):

Al2 (SO4) 3 (aq) + KOH (aq) - - - > Al (OH) 3 (aq) + 3K2SO4 (aq)

Now write a 6 in front of KOH in the left side, to balance K

Al2 (SO4) 3 (aq) + 6KOH (aq) - - - > Al (OH) 3 (aq) + 3K2SO4 (aq)

Now wirte a 2 before Al (OH) 3 in the right side to balance the OH radicals

Al2 (SO4) 3 (aq) + 6KOH (aq) - - - > 2Al (OH) 3 (aq) + 3K2SO4 (aq)

Now you can verifiy that the equation is balanced.

The answer is: Al2 (SO4) 3 (aq) + 6KOH (aq) - - - > 2Al (OH) 3 (aq) + 3K2SO4 (aq)