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15 October, 18:56

Calculate the energy absorbed when 6.20 g of aluminum is heated from 10.0°C to 65.0°C if the specific

heat of aluminum is 0.900 J/g°C

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Answers (1)
  1. 15 October, 19:22
    0
    306.9

    Explanation:

    You should follow this formula q=mc ΔT

    q = energy produced

    X

    m = mass of the product in grams

    X

    Δ = specific heat, the amount of heat it takes to raise the temp by 1 degree

    X

    final temp-initial temp / temperature already given
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