What is the density of lithium metal (in g/cm3) if a cube measuring 0.82 cm * 1.45 cm * 1.25 cm has a mass of 0.794 g?

First, determine the volume of the rectangular prism by multiplying its base, height, and width. That is,

Volume = Height x weight x length

Substituting the known values,

Volume = (0.82 cm) (1.45 cm) (1.25 cm) = 1.48625 cm³.

For calculation of the density, we divide the given mass by the total volume.

Density = 0.794 g/1.48625 cm³.

Answer: 0.534 g/cm³

Density is given by mass divided by the volume of a substance.

In this case the mass is 0.794 g and the volume is 0.82 cm * 1.45 cm * 1.25 cm = 1.48625 cm³.

Therefore, density = 0.794 / 1.48625

= 0.5342 g/cm³

Thus, the density of lithium metal is 0.5342 g/cm³