3 August, 00:36
What is the density of lithium metal (in g/cm3) if a cube measuring 0.82 cm * 1.45 cm * 1.25 cm has a mass of 0.794 g?
3 August, 01:00
Density is given by mass divided by the volume of a substance.
In this case the mass is 0.794 g and the volume is 0.82 cm * 1.45 cm * 1.25 cm = 1.48625 cm³.
Therefore, density = 0.794 / 1.48625
= 0.5342 g/cm³
Thus, the density of lithium metal is 0.5342 g/cm³
3 August, 02:11
First, determine the volume of the rectangular prism by multiplying its base, height, and width. That is,
Volume = Height x weight x length
Substituting the known values,
Volume = (0.82 cm) (1.45 cm) (1.25 cm) = 1.48625 cm³.
For calculation of the density, we divide the given mass by the total volume.
Density = 0.794 g/1.48625 cm³.
Answer: 0.534 g/cm³
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» What is the density of lithium metal (in g/cm3) if a cube measuring 0.82 cm * 1.45 cm * 1.25 cm has a mass of 0.794 g?