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3 August, 00:36

What is the density of lithium metal (in g/cm3) if a cube measuring 0.82 cm * 1.45 cm * 1.25 cm has a mass of 0.794 g?

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Answers (2)
  1. 3 August, 01:00
    0
    Density is given by mass divided by the volume of a substance.

    In this case the mass is 0.794 g and the volume is 0.82 cm * 1.45 cm * 1.25 cm = 1.48625 cm³.

    Therefore, density = 0.794 / 1.48625

    = 0.5342 g/cm³

    Thus, the density of lithium metal is 0.5342 g/cm³
  2. 3 August, 02:11
    0
    First, determine the volume of the rectangular prism by multiplying its base, height, and width. That is,

    Volume = Height x weight x length

    Substituting the known values,

    Volume = (0.82 cm) (1.45 cm) (1.25 cm) = 1.48625 cm³.

    For calculation of the density, we divide the given mass by the total volume.

    Density = 0.794 g/1.48625 cm³.

    Answer: 0.534 g/cm³
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