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7 September, 05:05

Which is the limiting reagent in the following reaction given that you start with 15.5 g of Na2S and 12.1 g CuSO4? Reaction: Na2S + CuSO4 → Na2SO4 + CuS A) Na2S B) CuSO4 C) Na2SO4 D) CuS E) not enough information

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  1. 7 September, 05:19
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    CuSO4

    Explanation:

    Na2S + CuSO4 → Na2SO4 + CuS

    The reaction is balanced (same number of elements in each side)

    To determine limiting reagent you need to know the moles you have of each.

    Molar mass Na2S = 23 * 2 + 32 = 78

    Molar mass CuSO4 = 63.5 + 32 + 16 * 4 = 159.5

    Na2S mole = 15.5 / 78 = 0.2

    CuSO4 mole = 12.1/159.5 = 0.076

    *Remember mole = mass / MM

    With that information now you have to divide each moles by its respective stoichiometric coefficient

    Na2S stoichiometric coefficient : 1

    Na2S : 0.2 / 1 = 0.2

    CuSO4 stoichiometric coefficient: 1

    CuSO4: 0.076 / 1 = 0.076

    The smaller number between them its the limiting reagent, CuSO4
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