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30 September, 12:32

A sample of gas isolated from unrefined petroleum contains 90.0% CH4, 8.9% C2H6, and 1.1% C3H8 at a total pressure of 307.2 kPa. What is the partial pressure of each component of this gas?

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  1. 30 September, 12:36
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    276.48 atm → CH₄

    27.3 atm → C₂H₆

    3.38 atm → C₃H₈

    Explanation:

    Percentages of each gas, are the mole fraction

    0.9 CH₄

    0.089 C₂H₆

    0.011 C₃H₈

    Mole fraction = Partial pressure each gas / Total pressure

    0.9 = Partial pressure CH₄ / 307.2 kPa

    307.2 kPa. 0.9 = 276.48 atm

    0.089 = Partial pressure C₂H₆ / 307.2 kPa

    307.2 kPa. 0.089 = 27.3 atm

    0.011 = Partial pressure C₃H₈ / 307.2 kPa

    307.2 kPa. 0.011 = 3.38 atm
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