The amount of protein in a sample was measured by the sample's absorbance of light at a given wavelength. Using standards, a best fit line (calibration curve) of absorbance (y-axes) vs. mg protein (x-axes) gave a slope of 0.0163 and an intercept of 0.104.

What is the amount of protein in an unknown sample that has an absorbance of 0.150?

Protein Concentration is 2.82mg/L

Explanation:

According to Beer-Lambert's Law, Absorbance is directly proportional to the concentration.

However, the concentration of a solution can be determined from a calibration curve, in which Absorbance is plotted on the y-axis and the Concentration on the x-axis.

Plotting the best line, the equation of line is used

y = mx + c

where y is absorbance = 0.150

m is slope = 0.0163

x is concentration

c is intercept = 0.104

inserting the values from the question

y = mx + c

0.150 = 0.0163x + 0.104

0.0163x = 0.150 - 0.104

0.0163x = 0.046

Divide both sides by 0.0163

0.0163x/0.0163 = 0.046/0.0163

x = 2.82

Concentration of protein = 2.82 mg/L