To make a gallon of sweet tea you have to heat the water to 100.00 °C. If the pot on

the stove contains 57.2 grams of water, and the temperature at the tap is 22.7 °C,

how much heat must be absorbed by the water?

Question

Clark Pena

Chemistry

21 August, 01:53

To make a gallon of sweet tea you have to heat the water to 100.00 °C. If the pot on

the stove contains 57.2 grams of water, and the temperature at the tap is 22.7 °C,

how much heat must be absorbed by the water?

+3

Answers (1)

Know the Answer?

Jordin Bradford · Answer 1

Q = 18.49kJ

Explanation:

Mass = 57.2g

T₁ = 22.7°C

T2 = 100°C

Specific heat capacity of water = 4.184J/g°C

Heat energy (Q) = ?

Q = MC∇T

Q = MC (T₂ - T₁)

Q = 57.2 * 4.184 (100 - 22.7)

Q = 57.2 * 4.184 * 77.3

Q = 18499.80J

Q = 18.49kJ

To make a gallon of sweet tea you have to heat the water to 100.00 °C. If the pot onthe stove contains 57.2 grams of water, and the temperature at the tap is 22.7 °C,how much heat must be absorbed by the water?

To make a gallon of sweet tea you have to heat the water to 100.00 °C. If the pot on

the stove contains 57.2 grams of water, and the temperature at the tap is 22.7 °C,

how much heat must be absorbed by the water?