In a similar analysis, a student determined that the percent of water in the hydrate was 25.3%. the instructor informed the student that the formula of the anhydrous compound was cuso4. calculate the formula for the hydrated compound.

Question

Roberto Church

Chemistry

2 April, 23:50

In a similar analysis, a student determined that the percent of water in the hydrate was 25.3%. the instructor informed the student that the formula of the anhydrous compound was cuso4. calculate the formula for the hydrated compound.

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Bryanna Murphy · Answer 1

Answer is: f ormula for the hydrated compound is CuSO ₄·3H₂O.

ω (H₂O) = 25,3% = 0,253.

ω (CuSO₄) = 100% - 25,3%.

ω (CuSO₄) = 74,7% = 0,747.

ω (H₂O) : M (H₂O) = ω (CuSO₄) : M (CuSO₄).

0,253 : M (H₂O) = 0,747 : 159,6 g/mol.

M (H₂O) = (0,253 · 159,6 g/mol) : 0,747.

M (H₂O) = 54 g/mol.

N (H₂O) = 54 g/mol : 18 g/mol.

N (H₂O) = 3.