Calculate the volume of c2h2 that is collected over water at 23 ∘c by reaction of 1.53 g of cac2 if the total pressure of the gas is 755 torr. (the vapor pressure of water is 21.07 torr.)

Weight of CaC2 is 1.53 g Temparature is 23 celcius T = 23 + 273K = 296K The pressure of the gas P = 755 torr Calculating the moles of CaC2 n = 1.53g x 64.0994 mol/g = 0.023869 moles PV = nRT V = nRT / P = > V = (0.023869 mol) x (62.3636 L Torr / K mol) x (296 K) / 755 torr Volume of C2H2 = 0.587 L