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23 July, 01:03

When 26.62 miles of FeS2 reacts with 5.44 miles of O2 how many miles of SO2 are formed

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  1. 23 July, 01:31
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    4 parts of FeS2 reacts with 11 parts of O2

    so 26,62 moles of FeS2 would need 26,62/4 * 11 = 73,2 moles of O2

    So only 5,44 / 11 * 4 = 1,98 moles of FeS2 reacts with 5,44 moles of O2, O2 is the limiting

    reactant

    This means FeS2 is the reactant in excess and 26,62 - 5,44 = 21,18 moles of FeS2 are left over

    and 1,98 * 8/4 = 3,96 moles of SO2 are formed
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